2x^2-5x-3600=0

Solution for 2x^2-5x-3600=0 equation:

2x^2-5x-3600=0

a = 2; b = -5; c = -3600;
Δ = b2-4ac
Δ = -52-4·2·(-3600)
Δ = 28825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28825}=\sqrt{25*1153}=\sqrt{25}*\sqrt{1153}=5\sqrt{1153}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5\sqrt{1153}}{2*2}=\frac{5-5\sqrt{1153}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5\sqrt{1153}}{2*2}=\frac{5+5\sqrt{1153}}{4}
$